All 4 caps are 4.7uf 25v. C3, between pins 1 and 3 shows open. C4 between 4 and 5 shows 2K ohms, C5 beween 1 and +Vcc shows 220 ohms, and C6 beween pin 6 and (I think) ground shows 32 ohms.
Is this of any help?
Thanks
I don't know if those resistance readings are norm or not. Some seem really low. Try reversing your ohm meter leads after getting first reading. If reading goes up, you are measuring through a forward biased junction in the chip. Reverse the leads to reverse bias the junction and see if reading jumps up.
Brian makes excellent point about the electrolytic caps. They could be your problem also.
As far as changing the chip, I am opening myself to flaming critique, but here goes it; you need a good solder sucker or "solder wick" to remove the solder from the IC holes. A small tip iron, if not temperature controlled, then 40-60 Watts is plenty. 60/40 or 63/37 flux based solder for the new chip. Hemostats or needle nose pliers to remove the old chips legs. Narrow bladed wire cutters to cut the leads.
Note the orientation of the chip and where the pin 1 notch is. Use your cutters to cut the leads of the old IC as close to the body as you can get. From component side of board, grip each cut leg with hemostats or needle nose pliers and flip board over and unsolder that lead while gently pulling on the ‘stats or needle nose. Once you have unsoldered and removed each of the old leads, clear solder from the holes using the solder sucker or the solder wick. If the new IC came in a black bag, or black foam, assuming you do not have an anti static wrist strap, touch the 7805 regulator by the metal tab as you remove the new chip from the foam and insert the new IC in the board. Solder each lead and cut excess lead length.
It isn’t difficult. Just avoid applying too much heat to the solder pads (i.e. no more than a few seconds) as you are unsoldering the old leads or soldering in the new. If you see the board starting to discolor, move on to next pad and come back after the board as cooled a little.
